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A point charge is positioned inside an imaginary cubic box (i.e. a Gaussian surface) whose side length is L. This smaller cube is placed inside a larger cube whose side length is 2 L. Which of the following is true regarding the electric flux going through the two cubic Gaussian surfaces?a. The flux through the large cube is twice that through the small cube. b. The flux through the large cube is eight times that through the small cube. c. Cannot determine the relationship between flux through the two cubes because the exact location of the point charge is unknown. d. The flux through the two cubes are the same. e. None of the other answers are true.

Respuesta :

The flux through the large cube is four times that through the small cube.

Electric flux is the rate at which the electric field flows through a given area. The electric flux is directly proportional to the number of electric field lines going through the virtual surface.

i.e. Flux is directly proportional to Area.

For an electric field, the mathematical relation between an enclosed charge and electric field is given by Gauss’s Law. It is one of the core law in electromagnetism. The Gauss law states that the total electric flux through a hypothetical closed surface is always equal to (1/ε0) times the net charge enclosed by the surface.
Let A1 = Area of gaussian surface with length L.

    A2= Area of gaussian surface with length 2L.

Since this is a cube, area of cube =  , where L = length of side

So, A1 =  and A2 =

On dividing these two, we get A1/A2 = 1/4

i.e. A2 = 4 A1

Hence the flux through the large cube is four times that through the small cube.

To know more about flux visit:
brainly.com/question/15521858

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