If the electron configuration of a diatomic molecule has 6 electrons in bonding orbitals and 2 electrons in antibonding orbitals, then the overall bond order is 2.
We know that bond order is = [tex]\frac{no of electron in bonding- antibonding}{2}[/tex]
so here no of electron on bonding is 6 and in antibonding orbital it is 2 so B.O.= 2
What is bond order?
The number of electron pairs that form bonds between two atoms is known as bond order. A single bond, a double bond, a triple bond, a quadruple bond, and so on have a bond order of one in a covalent bond between two atoms.
The number of electrons in the bonding molecular orbital (Nb) and the number of electrons in the antibonding molecular orbitals are what is known as the bond order (Na). Bond order is also known as the number of covalent bonds in a molecule, i.e., Bond order = (Nb-Na)/2.
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