The systematic name for the complex ion [CrBr₄(ox)]⁻³ is tetrabromooxalatochromate (III) ion. The oxidation number of Cr in [CrBr₄(ox)]⁻³ is +3.
For naming the compound, [CrBr₄(ox)]⁻³, one must find out the ligand. The ligand is bromine. There are four bromine atoms, therefore, the prefix used here is tetra. Chromium metal is cationic in nature.
The oxidation state of [CrBr₄(ox)]⁻³ is calculated as:-
x + 4(-1) + (-2) = -3
x = +3
The oxidation state of chromium is (III). Therefore, the name of the compound [CrBr₄(ox)]⁻³ is tetrabromooxalatochromate (III) ion, and the oxidation state of Cr is +3.
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