a car is moving with speed 60 m/s and acceleration 4 m/s2 at a given instant. using a second-degree taylor polynomial, estimate how far the car moves in the next second__m

Respuesta :

The automobile is expected to go 62 meters in the following second.

Explain the second-degree taylor polynomial?

  • Quadratics are a common term used to describe degree 2 polynomials.
  • A second degree Taylor polynomial at x=a is indeed the best quadratic approximation of f(x) close a, just as the tangent line to f(x) at x=a is the greatest linear approximation of f(x) near a.

Let a function in values of time reflect the location of the car:

x = f(t) ...eq 1

A second-degree Taylor polynomial can be used to estimate the position of the car in time:

x = x0 + v0/1!×t + a0/2!×t²

x =  x0 + v0.t + 1/2.a0.t²

Where:

  • x0 - The starting location, in meters.
  • v0- The starting speed, expressed in meters per second.
  • a0- The initial acceleration, expressed in m/s2.
  • t- The passing of seconds.

If we are aware of, x0 = 0m, v0 = 60 m/s, t = 1 sec and a0 = 4 m/s2 , therefore the subsequent second's distance is:

x =  0 + (60).1 + 1/2.(4).1²

x = 62 m.

Thus, the automobile is expected to go 62 meters in the following second.

To know more about the second-degree taylor polynomial, here

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