The change in kinetic energy of the system is 160.89 Joules
Kinetic energy is a from of energy that an particle has has by reason we must apply a force. We know that Kinetic energy is the energy due to the velocity of spoed of the moving object.
It is given that,mA = 2kg
Mass of object A,= 15 m/s
Initial speed of object A,
Mass of object B, =5kb
Initial speed of object A, (at rest)= 0
Le V is the final speed when they lock and move with one common velocity. Using the conservation of momentum to find it.
V= 2×15/(2+5)
V=4.28
V = 4.28 m/s
Initial kinetic energy of the system is :the change in kinetic energy of the system is 160.89 Joules
Ki= 1/2 ×2×(15)^2
Ki=225j
Final kinetic energy of the system is :
Kf= 1/2(ma+mb)^V2
Kf= 1/2 ×(2+5)×(4.28)^2
Kf=225 j
Kf=64.11 j
Let is the change in kinetic energy of the system after the collision. It is given by :
∆K=∆k-∆i
∆K=64.11-225
∆K=-160.89 J
So, the change in kinetic energy of the system is 160.89 Joules.
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