The amount of plastic needed for each batch of 50 coins is equal to the volume of 50 coins that is 80 cu.cm.
The diameter of the coin is 2.0 cm.
As radius is half of the diameter, so its radius will be 1.0 cm.
It is given that the coin is circular in shape, so the area of the circular surface will be πr² = 3.14 × 1² = 3.14 sq. cm. (π = 3.14)
The thickness of the coin is 0.5 cm, which will be considered as the height of the coin.
So, the volume of each coin will be = 3.14 × 0.5 = 1.57 cu. cm.
Therefore, the plastic needed for the batch of 50 coins is,
1.57 × 50 = 78.5 cu.cm and in multiple of 10 it will be 80 cu.cm.
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