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the synthesis of ch3oh(g) from co(g) and h2(g) is represented by the equation above. the value of kc for the reaction at 483 k is 14.5. a mixture of co(g) and h2(g) is pumped into a previously evacuated 2.0 l reaction vessel. the total pressure of the reaction system is 1.2 atm at equilibrium. what will be the total equilibrium pressure of the system if the volume of the reaction vessel is reduced to 1.0 l at constant temperature? responses less than 1.2 atm less than 1.2 atm greater than 1.2 atm but less than 2.4 atm greater than 1.2 atm but less than 2.4 atm 2.4 atm 2.4 atm greater than 2.4 atm

Respuesta :

According to Boyle's law which is a law for constant temperature the  the total equilibrium pressure of the system if the volume of the reaction vessel is reduced to 1.0 l  is 2.4 atmospheres.

What is Boyle's law?

Boyle's law is an experimental gas law which describes how the pressure of the gas decreases as the volume increases. It's statement can be stated as, the absolute pressure which is exerted by a given mass of an ideal gas is inversely proportional to its volume provided temperature and amount of gas remains unchanged.

Mathematically, it can be stated as,

P∝1/V or PV=K. The equation states that the product of of pressure and volume is constant for a given mass of gas and the equation holds true as long as temperature is maintained constant.

According to the equation the unknown pressure and volume of any one gas can be determined if two gases are to be considered.That is,

P₁V₁=P₂V₂

Substitution in above equation gives P₂=1.2×2/1=2.4 atmospheres.

Hence, the total equilibrium pressure of the system if the volume of the reaction vessel is reduced to 1.0 l  is 2.4 atmospheres.

Learn more about Boyle's law,here:

https://brainly.com/question/1437490

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