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7. Sylvia went on a trip. The number of shirts she packed was 2 fewer than twice the number of pants
she packed. The total number of pairs of pants and shirts was 16.
A. Let x the number of pants she packed and let y = the number of shirts she packed. Write a system of
equations to represent the problem.
B. Solve the system of equations using substitution to find the number of shirts and pairs of pants Sylvia
brought.

Respuesta :

Pizzarocks101

Answer:

10 shirts, 6 pants

Step-by-step explanation:

Let y = the number of shirts

Let x = the number of pants

y + 2 = 2x

x + y = 16

y = 2x - 2

x + (2x - 2) = 16

3x = 18

x = 6

y + 6 = 16

y =  10

semsee45

Answer:

[tex]\textsf{A.} \quad \begin{cases}y=2x-2\\x+y=16\end{cases}[/tex]

[tex]\textsf{B. \quad 6 pants and 10 shirts}[/tex]

Step-by-step explanation:

Part A

Given variables:

  • Let x = the number of pants Sylvia packed.
  • Let y = the number of shirts Sylvia packed.

If the number of shirts Sylvia packed was 2 fewer than twice the number of pants she packed:

[tex]\implies y=2x-2[/tex]

If the total number of pairs of pants and shirts was 16:

[tex]\implies x+y=16[/tex]

Therefore, the system of equations that represents the problem is:

[tex]\begin{cases}y=2x-2\\x+y=16\end{cases}[/tex]

Part B

System of equations:

[tex]\begin{cases}y=2x-2\\x+y=16\end{cases}[/tex]

Substitute the first equation into the second equation and solve for x:

[tex]\implies x+2x-2=16[/tex]

[tex]\implies 3x-2=16[/tex]

[tex]\implies 3x=18[/tex]

[tex]\implies x=6[/tex]

Substitute the found value of x into the first equation and solve for y:

[tex]\implies y=2(6)-2[/tex]

[tex]\implies y=12-2[/tex]

[tex]\implies y=10[/tex]

Therefore, Sylvia packed:

  • 6 pants
  • 10 shirts

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