The mass of 9.45moles of Ba(OH)₂ is 1618.975grams.
The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass as follows:
mass = no of moles × molar mass
According to this question, there are 9.45moles of Ba(OH)₂. The molar mass of the barium hydroxide was given as 171.32g/mol.
mass = 9.45 mol × 171.32 g/mol
mass = 1618.975grams.
Therefore, 1618.975grams is the mass of the barium hydroxide.
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