Respuesta :
The magnitude of the linear momentum of the electron that is initially at rest just after the collision with the photon is Pe = 6.626 * [tex]10^{-34}[/tex] ( λ' - λ ) / λ λ' kg m / s
λ' - λ = h / [tex]m_{e}[/tex] c ( 1 - cos Φ )
λ = Initial wavelength
λ' = Final wavelength
h = Planck's constant
[tex]m_{e}[/tex] = Mass of electron
c = Speed of light
h = 6.626 * [tex]10^{-34}[/tex] J s
[tex]m_{e}[/tex] = 9.1 * [tex]10^{-31}[/tex] kg
c = 3 * [tex]10^{8}[/tex] m / s
Φ = 180°
λ' = λ + [ 6.626 * [tex]10^{-34}[/tex] / 9.1 * [tex]10^{-31}[/tex] * 3 * [tex]10^{8}[/tex] ( 1 + 1 ) ]
λ' = λ + ( 0.485 * [tex]10^{-11}[/tex] ) m
Pp λ = Pe + Pp λ'
Pe = h / λ - ( - h / λ' )
Pe = h ( 1 / λ - 1 / λ' )
Pe = 6.626 * [tex]10^{-34}[/tex] ( λ' - λ ) / λ λ' kg m / s
Therefore, the magnitude of the linear momentum of the electron just after the collision with the photon is Pe = 6.626 * [tex]10^{-34}[/tex] ( λ' - λ ) / λ λ' kg m / s
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