It will take 0.78s for him to reach the water when he drops himself from a 3m high diving board using 9.8 m/s² earth gravity.
It is the net acceleration that is imparted to objects due to the combined effect of gravitation (from mass distribution within earth) and the centrifugal force (from the earth's rotation). It is given by the norm g.
How to calculate how many seconds does it take for him to reach the water using 9.8m/s² earth gravity?
Vf = [tex]\sqrt{2*g*h}[/tex]
= [tex]\sqrt{2*9.8*3}[/tex]
Vf = 7.67 m/s (rounded)
Vf = Vi + g*t
7.67 = 0 + 9.8 * t
t = [tex]\frac{7.67}{9.8}[/tex]
t = 0.78s (rounded)
So It takes 0.78s before a boy reach the water when he drops himself from a 3m high diving board using 9.8m/s² earth gravity.
Learn more about earth gravity https://brainly.com/question/8844454
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