a solid sphere of mass 2.36 kg and radius 0.660 m is rolling without slipping along a horizontal surface with a linear speed of 5.80 m/s. what is its total kinetic energy?

Respuesta :

The total kinetic energy is 3.148 joule.

We need to know about kinetic energy to solve this problem. Kinetic energy is the energy from a moving object. It can be determined as

KE = 1/2 . m . v²

where KE is kinetic energy, m is mass and v is speed.

The rotational kinetic energy can be defined as

KErotation = 1/2 . I . ώ²

where I is moment of inertia and ώ is the angular velocity.

From the question above, we know that solid sphere has parameters

m = 2.36 kg

R = 0.66 m

v = 5.8 m/s

Find the moment of inertia

I = 2/5 m . R²

I = 2/5 . 2.36 . 0.66²

I = 0.411 kgm²

Find the angular velocity

ώ = v / R

ώ = 2.36 / 0.66

ώ = 3.58 rad/s

The linear kinetic energy is

KE = 1/2 . m . v²

KE = 1/2 . 2.36 . 0.66²

KE = 0.514 joule

The angular kinetic energy is

KErotation = 1/2 . I . ώ²

KErotation = 1/2 . 0.411 . 3.58²

KErotation = 2.634 joule

Hence, the total kinetic energy is

KE total = KE + KErotation

KE total = 0.514 + 2.634

KE total = 3.148 joule

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