Hydrogen atom is in the ground state and absorbs light with a wavelength of 102.6 nm, the energy level of the resulting excited state will be 3.
Ground state (nₐ) = 1
excited state (nₓ) = ?
wavelength = 102.6 nm or 102.6 × 10⁻⁹
Calculate the frequency
v = c / λ
v = 3 × 10⁸ m/s / 102.6 × 10⁻⁹
v = 2.923 × 10¹⁵ s⁻¹
Now calculate the energy
E = nhv
E = 1 × 6.63 × 10⁻³⁴ Js⁻¹ × 2.923 × 10¹⁵ s⁻¹
E = 1.9379 × 10⁻¹⁸
Calculate the excited state (nf) by using the following equation
dE = Rₙ.Z² [ 1 / nₐ² - 1 / nₓ²]
1.9379 × 10⁻¹⁸ ] = 2.18 × 10⁻¹⁸ ] × 1² [1 / 1² - 1 / nₓ²]
1 / nₓ² = 1 - 0.8889
nₓ² = 1 / 0.111
nₓ² = 9
nₓ = 3
You can also learn about energy levels from the following question:
https://brainly.com/question/17396431
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