Respuesta :
The amount of mass potassium hydroxide (KOH) required to react with every 1.25 g of aluminum is 2.58 g.
The amount of mass potassium hydroxide (KOH) required can be calculate as follow:
as we know;
Mass of pure aluminum = 1.25g
Molar mass of KOH = 56 g/mol
The chemical reaction of a given element is given by:
[tex]2Al + 2 KOH + 6H_2O = > 2K^{+} +2Al(OH)^{4-} +3 H^{+}[/tex]
From the above reaction, we can deduce that:
2 mol AL ----- 2 mol KOH
How many moles of aluminum are needed for 1.25g?
[tex]n Al =\frac{ g}{mw} \\n Al =\frac{ 1.25}{27}\\nAl = 0.046 moles[/tex]
The mass of KOH required for 0.046 moles of aluminum is calculated as:
Mass Required = 0.046 x 56
Required mass = 2.58 g
Therefore, the amount of mass potassium hydroxide (KOH) required to react with every 1.25 g of aluminum is 2.58 g.
Learn more about mass potassium hydroxide here:
Brainly.com/question/13763130
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