a 25.0 ml sample of 0.150 m lactic acid is titrated with a 0.150 m naoh solution. what is the ph after 26.0 ml of base is added? the ka of lactic acid is 1.4

Respuesta :

The pH after 26.0ml of base is added is 11.46

What is pH?

In chemistry, pH, historically denoting "potential of hydrogen", is a scale used to specify the acidity or basicity of an aqueous solution. Acidic solutions are measured to have lower pH values than basic or alkaline solutions.

How to calculate the pH to answer the question?
Lactic acid is a weak acid. Let's assume lactic acid = HA

HA + NaOH --------------------------> NaA + H₂O
initially
milimoles of acid = 25 * 0.15 = 3.75
milimoles of NaOH added = 26 * 0.15 = 3.90
excess NaOH left after reacts with acid

milimoles of NaOH left = 3.9 - 3.75 = 0.15
total volume = 25 + 26 = 51ml
(NaOH) = 0.15 / 51 = 0.0029M
as NaOH is strong acid, it dissociates completely
so (NaOH) = (OH⁻) = 0.0029M
now

pOH = - log (OH⁻)
pOH = - log (0.0029)
pOH = 2.53
pH = 14 - 2.54

pH = 11.46

So based on the calculation, the pH after 26ml of base is added equal to 11.46

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