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an object of mass 0.8 kg is attached to an ideal horizontal spring of spring constant 180 n/m. the object is initially at rest at equilibrium. how much work would it take to set the object into an oscillation with amplitude 0.02 m?

Respuesta :

0.072 J is the work would the spring take to set the object into an oscillation with amplitude 0.02 m

What is amplitude?

A periodic variable's amplitude is a gauge of its change over a single period. A non-periodic signal's magnitude in relation to a standard value is its amplitude. There are several ways to define amplitude, and they are all dependent on how much the extreme values of the variable deviate from one another.

What is a spring constant?

The stiffness of the spring is how we determine spring constant. In other words, we can define the spring constant as the force used to produce the specified displacement when the spring's displacement is one unit. It follows that a spring's spring constant will increase with increasing spring stiffness.

Now to calculate the work done by spring we use the Hookes’s law

F=kx

Where F is the force required

K is the spring constant

X is the amplitude or distance

So F=kx

F=180x0.02

F=3.6 N

Now to calculate work :

Work = Force × Distance.

Work=3.6 N x0.02m

Work =0.072 J

Hence, 0.072 J is the work would the spring take to set the object into an oscillation with amplitude 0.02 m

To know more about the spring constant visit

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