A 500. Ml aqueous solution of na3po4 (molarmass=164g/mol) was prepared using 82g of the solute. What is the molarity of na3po4 in the resulting solution?.

Respuesta :

The molarity of Na₃PO₄ in the solution is 1 M.

What is molarity?
Molar concentration
, also known as molarity, amount concentration, or substance concentration, is a unit used to describe the amount of a substance in a solution expressed as a percentage of its volume. The number of moles per litre, denoted by the unit symbol mol/L as well as mol/dm3 in SI units, is the most widely used unit for molarity in chemistry. One mol/L of a solution's concentration is referred to as one molar, or 1 M.

From the question,

We are to determine the molarity of the solution.

First, we will determine the number of moles of the solute (Na₃PO₄) present

Mass of Na₃PO₄ = 82 g

Using the formula

[tex]number of moles = mass/molar mass[/tex]

Molar mass of Na₃PO₄ = 163.94 g/mol

∴ Number of moles of Na₃PO₄ present = [tex]82/163.94[/tex]

Number of moles of Na₃PO₄ present = 0.500 moles

Now, for the molarity of the solution

Using the formula
Molarity = no. of moles/volume

Volume of the solution = 500 mL = 0.5 L

∴ Molarity of the solution = [tex]0.500/0.5[/tex]

Molarity of the solution = 1 M

Hence, the molarity of the solution is 1 M.

To learn more about molarity click on the given link:

https://brainly.com/question/14469428

#SPJ4