Option C and E are the factors that allow sequencing by the sanger chain-termination method: It is impossible to extend a DNA strand whose 3' end ends in a dideoxynucleotide, and New nucleotides are added only to the 3' end of a growing DNA strand, respectively.
The chain is made up of deoxynucleotides with hydroxyl groups at the 3′ position of the deoxyribose ring. DNA polymerase adds the next nucleotide by connecting the phosphate of the incoming nucleotide to the 3′-hydroxyl of the departing nucleotide. In the absence of the 3′-hydroxyl, a nucleotide chain breaks, and the chain cannot be repaired. Only the 3' end of a developing DNA strand receives additional nucleotides. This is due to the fact that the strand only lengthens from the chain's 5' to 3' end.
Chain termination sequencing requires deoxynucleotides, a single-stranded DNA template, DNA polymerase, and a primer, just like DNA replication. During in vitro sequencing procedures, these components are combined, and DNA polymerase makes numerous copies of the original template.
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Complete question is:
Which factors make sequencing by the sanger chain-termination method possible? select all that apply.
a. Complementary single-stranded nucleic acid sequences can come together to form a duplex molecule.
b. Single-stranded nucleic acid molecules can be immobilized on certain types of filter paper.
c. A DNA strand whose 3' end terminates in a dideoxynucleotide cannot be elongated.
d. Duplex nucleic acid molecules can be separated by size by means of electrophoresis.
e. New nucleotides are added only to the 3' end of a growing DNA strand.
