The factors make sequencing by the sanger chain-termination method possible are option C and E: A DNA strand whose 3' end terminates in a dideoxynucleotide cannot be elongated.
Deoxynucleotides having hydroxyl groups at the 3′ position on the deoxyribose ring make up the chain. By joining the phosphate of the incoming nucleotide to the 3′-hydroxyl of the outgoing nucleotide, DNA polymerase adds the following nucleotide. A nucleotide chain cannot continue if it lacks the 3′-hydroxyl, and the chain is broken. A growing DNA strand only gets new nucleotides at the 3' end. This is because the strand elongates only from 5' to 3' end of the chain.
Similar to DNA replication, chain termination sequencing needs deoxynucleotides, a single-stranded DNA template, DNA polymerase, and a primer. These elements are combined during in vitro sequencing operations, and DNA polymerase creates several copies of the original template.
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Which factors make sequencing by the sanger chain-termination method possible? select all that apply.
a. Complementary single-stranded nucleic acid sequences can come together to form a duplex molecule.
b. Single-stranded nucleic acid molecules can be immobilized on certain types of filter paper.
c. A DNA strand whose 3' end terminates in a dideoxynucleotide cannot be elongated.
d. Duplex nucleic acid molecules can be separated by size by means of electrophoresis.
e. New nucleotides are added only to the 3' end of a growing DNA strand.
