at a certain concentration of h2 and nh3, the initial rate of reaction is 22.0 m / s. what would the initial rate of the reaction be if the concentration of h2 were halved? be sure your answer has the correct number of significant digits.

In chemistry and related fields, the idea of concentration is used frequently. It is a way to gauge how much of one substance is incorporated into another.

What is initial rate?

When a reaction first begins, or when t = 0, its initial rate is the rate that exists at that precise moment. At time zero (t), the slope of the reactant concentration versus the time curve is equal to the initial rate.

Rak=k(H₂) (NH₃) Rak law expression

1. reaction order w.r.t H₂ is ⇒2

2. reaction order w.r.t NH₃ is⇒ 1.

3. overall order 2+1=3 ( bird order reaction)

4. k(H₂) (NH₃)= 0.740⇒ 1

H₂ is doubled ⇒ r₂=k(H₂) (NH₃)=4k(H₂) (NH₃)⇒2

(2)/(1) = r₂/r₁ = 4k(H₂) (NH₃)/k(H₂) (NH₃)=4

r₂= 4∝ r₁ = 4∝ 0.740=2.96m/s

5. r= 6.0∝ 10^⁴m/s, (H₂)= 0.98m, (NH₃)= 0.31m

r=k(H₂) (NH₃)

k=r/(H₂) (NH₃)= 6.0 ∝ 10^⁴/(0.98)^²(0.31)=201528.93m^⁻²s^⁻¹

K=2.0 ∝ 10^5m^⁻²s^⁻¹

Therefore, the significant digit is K=2.0 ∝ 10^5m^⁻²s^⁻¹

Learn more about concentration from the given link.

https://brainly.com/question/17206790

#SPJ4