The largest amount of Al₂O₃ produced from the reaction is 3.5 moles
What are limiting reactants?
A reactant that is completely consumed at the end of a chemical reaction is known as the limiting reagent. This reagent regulates the amount of product produced because the reaction cannot proceed without it.
Finding the limiting reactant,
4Al + 3O₂ —> 2Al₂O₃
From the balanced equation above,
4 moles of Al reacted with 3 moles of O₂.
Therefore,
7 moles of Al will react with = (7 × 3)/4 = 5.25 moles of O₂
From above, only 5.25 moles of O₂ out of 11 moles given, is needed to completely react with 7 moles of Al.
Therefore, Al is the limiting reactant and O₂ is the excess reactant.
Now, the largest amount of Al₂O₃ produced from the reaction. This can be obtained by using the limiting reactant as shown below
From the balanced equation above,
4 moles of Al reacted to produce 2 moles of Al₂O₃.
Therefore,
7 moles of Al will react to produce = (7 × 2)/4 = 3.5 moles of Al₂O₃.
Thus, the largest amount of Al₂O₃ produced from the reaction is 3.5 moles
To learn more about limiting reactants follow the link:
brainly.com/question/15230635
#SPJ4