All the real numbers x which satisfy the given inequality x²<4 , in interval form is (-2, 2).
As given in the question,
Given inequality is given by :
x²< 4
Simplify the given inequality x² < 4 to get all the real numbers x we have,
x² < 4
⇒ x² - 4 < 0
⇒ x² - 2² < 0
Apply a² - b² = ( a - b ) ( a + b ) we get,
⇒ ( x - 2 ) ( x + 2 ) < 0
⇒ x ∈ ( -2 , 2 ) as less than symbol represent open interval.
Therefore, all the real numbers x which satisfy the given inequality x²<4 , in interval form is (-2, 2).
The complete question is :
Find all real numbers x such that x^2 < 4. Give your answer in interval notation.
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