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H2Se(g) + 4 O2F2(g) SeF6(g) + 2 HF(g) + 4 O2(g)
30. Which of the following is true regarding the reaction represented above?
(A) The oxidation number of O does not change.
(B) The oxidation number of H changes from −1 to +1.
(C) The oxidation number of F changes from +1 to −1.
(D) The oxidation number of Se changes from −2 to +6.
(E) It is a disproportionation reaction for F.

Respuesta :

H2Se(g) + 402F2(g) ⇒SeF6(g) + 2HF(g) + 4O2(g) is true regarding following points ;

B. the oxidation number of H changes from -1 to +1 we can see as in H2Se changes to 2F.

C. the oxidation number of F changes from -1 to +1 we can see in O2F2 to        

     4O2.

D. the oxidation number of Se changes from -2 to +6 as we can see in H2Se to SeF6.

oxidation number also called oxidation state, is the total number of electrons that an atom either gains or loses in order to form a chemical bond with another atom.

disproportionation reaction is the type of reaction when the compound is converted into 2 oxidation states one of higher and one of lower oxidation state.

learn more about oxidation number here;

https://brainly.com/question/27239694

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