The area of a triangle whose vertices are r(3, 4), s(6, 2), and t(7, 10) is calculated to be 9.5 units²
Given that,
Vertices are r(3, 4), s(6, 2), and t(7, 10) which means ,
(x₁,y₁) = (3,4)
(x₂,y₂) = (6,2)
(x₃,y₃) = (7,10)
From formula,
The triangle area
A= 1/2 (|x₁(y₂ -y₃) + x₂(y₂ - y₁) + x₃(y₁ -y₂))
A=1/2(3(2 - 10) + 6(2-4) + 7(4-2))
A = 1/2 (3* -7 + 6* -2 +7* 2 )
A = 1/2 |(-21-12+14)|
A = 1/2 (19)
A = 9.5 units²
area of triangle is 9.5 units² with the given vertices.
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