The molar mass of the protein dissolved to form the solution will be: 13963.42 g/mol.
Molar mass is defined as mass of a substance in grams divided by the number of moles of the solute.
According to the question:
Mass of protein (w₂)= 100 g = 0.1g
Temperature (T) = 25°C = 298 K
R = 0.0821 L atm mol⁻¹ K⁻¹
π= 13.33 mm of Hg = [tex]\frac{13.33}{760}[/tex] = 0.0175 atm
Volume of solution = 1o mL = 0.01L
Using the formula,
M₂ = (W₂RT) / (πV)
M₂ = (0.1×0.082×298) / (0.0175×0.01) = 13963.42 g/mol.
Therefore the molar mass of the protein is 13963.42 g/mol.
The given question is incomplete, the complete question is:
100 mg of an unknown protein is dissolved in just enough water to make 10.0 mL of solution. the osmotic pressure of this solution is measured to be at 13.3 mm Hg at 25°C. Calculate the molar mass of the protein.
[R=0.0821 L atm mol⁻¹ K⁻¹ and 760 mm Hg= 1 atm]
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