Respuesta :
The probability that the first drawing gives green ball and second drawing a red ball is 2/7
Number of green balls = 4 green balls
Number of red balls = 4 red balls
Total number of balls in the bag = 4 + 4
= 8 balls
The probability = Number of favorable outcomes / Total number of outcomes
The probability of getting green balls in first draw = 4 / 8
= 1/2
First ball drawn was not replaced before drawing the second one
The probability of getting red ball in second draw = 4 / 7
The probability that the first drawing gives green ball and second drawing a red ball = (4/8) × (4/7)
= 2/7
Hence, the probability that the first drawing gives green ball and second drawing a red ball is 2/7
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