A pipet is used to transfer 5.00 mL of a 1.25 M stock solution in flask "S" to a 25.00-mL volumetric flask "B," which is then diluted with DI H20 to the calibration mark. The solution is thoroughly mixed. Next, 2.00 mL of the solution in volumetric flask "A" is transferred by pipet to a 50.00-ml volumetric flask "B" and then diluted with DI H20 to the calibration mark. Calculate the molarity of the solution in vol- umetric flask "B."

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ShubhamSrivastava ShubhamSrivastava · Answer 1 · 2022-11-18T17:18:03+01:00

The molarity of the solution in the volumetric flask B is 0.0100 M.

This problem is solved firstly by using the concept of dilution formula which can be written as below:

M1V1 = M2V2

Given,

M1 = 1.25 M

V1 = 5 ml

V2 = 25 ml

By substituting all the values, we get

1.25 × 5 = M2 × 25 ml

M2 = 1.25 × 5 / 25

M2 = 0.25 M

Now,

Volume of solution pipet from volumetric flask A V2 = 2 ml

Molarity of solution in volumetric flask 'A' = 0.25 M = M2

Volume Volume of solution in volumetric flask B (V3) = 50 ml

Again by using dilution formula,

M2V2 = M3V3

By substituting all the values, we get

0.25 × 2 = M3 × 50 ml

M3 = 0.0100 M

Thus, we concluded that the molarity of the solution in the volumetric flask B is 0.0100 M.

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