a) The standard error of the mean is 0.90
b) The marginal error is 1.76
Given,
Number of samples in the population, n = 60
Sample mean of the population, μ = 25
Standard deviation of the population, σ = 7
We have to find the standard error of the mean and the margin of error at 95% confidence.
Here,
a) The standard error of the mean = Standard deviation / root of sample
= σ / √n
= 7/√60
= 0.90
b) The margin error;
Zₐ/₂ × σ / √n
= Zₐ/₂ × 7/√60
= 1.96 × 0.90
= 1.76
Therefore,
a) The standard error of the mean is 0.90
b) The marginal error is 1.76
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