A simple random sample of 60 items resulted in a sample mean of 25. The population standard deviation is o = 7. (Round your answers to two decimal places.) (a) What is the standard error of the mean, 0-? (b) At 95% confidence, what is the margin of error?

Respuesta :

a) The standard error of the mean is 0.90

b) The marginal error is 1.76

Given,

Number of samples in the population, n = 60

Sample mean of the population, μ = 25

Standard deviation of the population, σ = 7

We have to find the standard error of the mean and the margin of error at 95% confidence.

Here,

a) The standard error of the mean = Standard deviation / root of sample

= σ / √n

= 7/√60

= 0.90

b) The margin error;

Zₐ/₂ ×  σ / √n

= Zₐ/₂ × 7/√60

= 1.96 × 0.90

= 1.76

Therefore,

a) The standard error of the mean is 0.90

b) The marginal error is 1.76

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