for a fixed location, the number of sunlight hours in a day fluctuates throughout the year. suppose that the number of daily sunlight hours in a particular location can be modeled by the following. l(t)

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On October 24, 218 days after March 20, there will be 10 hours of sunlight.

The number of daily sunlight hours of a particular location is modelled by the trigonometric equation,

l(t) = 12 + 3.5sin (2[tex]\pi[/tex]/365t)

Here , L(t)= Number of sunlight hours in a day.

           t = Number of days after 20th March .

Now we are required to determime the day  during first 365 on which there are 10 sunlight hours ,that is, we need the value of "t" for which L(t) =10 hours. So in the given equation by putting L(t)= 10 and solving for t , follows as,

l(t) = 12 + 3.5sin (2[tex]\pi[/tex]/365t)

10 = 12 + 3.5sin (2[tex]\pi[/tex]/365t)

10-12 = 3.5sin (2[tex]\pi[/tex]/365t)

-2 =  3.5sin (2[tex]\pi[/tex]/365t)

-2/3.5 = sin (2[tex]\pi[/tex]/365t)

-0.574 = sin (2[tex]\pi[/tex]/365t)

For the inverse function of y = sin x

sin ⁻¹(y) =x + 2n[tex]\pi[/tex]

Now as we are required to calculate the day having 10 sunlight hours in first 365 days so putting n=0 we get,

t = -35.3521 or t =217.9422

Now t can not be negative as we want to find the day after march 20 having 10 sunlight hours. So neglecting t=-35.3521 . Now we get t=217.9422 .

Rounding off we get ,t=218 which is the required answer.

Hence, 218 days after march 20 i.e on October 24 it will have 10 sunlights.

Learn more about trigonometric equation here:

brainly.com/question/27821667

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