The ordered pair that is not a solution to the inequality y ≥ 2x² - 4x + 2 is given as follows:
(-1,6).
The inequality is presented as follows:
y ≥ 2x² - 4x + 2.
Then for each pair, the numeric value is calculated, replacing x and y by it's respective coordinates, and when a false statement is generated, the ordered pair is not a solution to the inequality.
For the first ordered pair, (-1, 6), the numeric value of the inequality is given as follows:
6 ≥ 2(-1)² - 4(-1) + 2
6 ≥ 8.
Which is a contradiction, hence it is not a solution to the inequality.
For the pair (1,0), we have that:
0 ≥ 2(1)² - 4(1) + 2
0 ≥ 0.
Which is true, hence it is a solution.
For the pair (0,3), we have that:
3 ≥ 2(0)² - 4(0) + 2
3 ≥ 2
Hence it is also a solution.
For the pair (2,5), we have that:
5 ≥ 2(2)² - 4(2) + 2
5 ≥ 2
Hence it is also a solution.
The problem is given by the image shown at the end of the answer.
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