HW1.
The vertices of a triangle ABC are A(2, 1), B(-2, 3) and C(4, 5). Find the equation of the median through the
vertex A
A
Assume D be the midpoint of BC

Respuesta :

Answer:

  y = -3x +7

Step-by-step explanation:

You want the equation of the median line through point A, given that the vertices of the triangle are A(2, 1), B(-2, 3) and C(4, 5).

Midpoint of BC

The median will go through the midpoint of the segment opposite vertex A. That midpoint is ...

  D = (B +C)/2

  D = ((-2, 3) +(4, 5))/2 = (-2+4, 3+5)/2 = (2, 8)/2 = (1, 4)

Slope

The slope of the line is given by the slope formula:

  m = (y2 -y1)/(x2 -x1)

Then the slope of AD is ...

  m = (4 -1)/(1 -2) = 3/-1 = -3

Point-slope equation

The point-slope equation of the line with slope m through point (h, k) is ...

  y -k = m(x -h)

The equation of the line with slope -3 through point A(2, 1) is ...

  y -1 = -3(x -2) . . . . . equation of the median line

This can be simplified to slope-intercept form:

  y = -3x +6 +1 . . . . . eliminate parentheses, add 1

  y = -3x +7 . . . . . slope-intercept equation of the median line

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