Answer:
B. 8 years
Explanation:
D = 1 a.u. - Distance from the Sun to the Earth in astronomical units (a.u.)
D₁ = 4 a.u - Distance from the Sun to the planet
T = 1 year - The period of the earth's revolution around the Sun
__________
T₁ - ? - The period of revolution of the planet around the Sun
Kepler's law
(T₁/T)² = (D₁/D)³
(T₁ / 1)² = (4 / 1)³
T₁² = 64
T₁ = √ 64 = 8 years
B. 8 years
The relationship between the planet's period and the Earth's period and cube root of the ratio between the planet's distance from the Sun and the Earth's distance from the Sun.
Kepler's third law is the theory applied to this puzzle.
Write the expression for the period of the planet first using Kepler's rule to take into account the period of the Earth, the distance from the Sun to the Earth, and the distance from the Sun to the planet.
To compute the period of the planet, finally, substitute the appropriate quantities. The relationship between the period and the separation between the Sun and the planet is provided by, in accordance with Kepler's third law: T² ∝ a³
T is the period in this case, and an is the separation between the planet and the Sun.
To know more about Kepler's third law, click on the link below:
https://brainly.com/question/6867220
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