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This figure consists of a rectangle and a quarter circle.

What is the perimeter of this figure?

Use 3.14 for π .

Enter your answer as a decimal. Thank you in advance

This figure consists of a rectangle and a quarter circle What is the perimeter of this figure Use 314 for π Enter your answer as a decimal Thank you in advance class=

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kaevras
The hardest part of this would be finding the length of that arc. Though, since it's a quarter circle, it makes our job a whole lot easier.

The circumference of a circle is 2πr, therefore, a quarter circumference of a circle would be (2πr) / 4.

Therefore, the length of that arc would be (2 * 3.14 * 8) / 4 = 12.56


With this figure, we can just add up the rest of the perimeter.

12.56 + 8 (circle radius) + 10 + 10 (two rectangle heights) + 17 (rectangle length) + 9 (rectangle length minus radius, for the top-right part of the rectangle), giving us an answer of 66.56cm

The perimeter of the given figure is 66.56 cm

Calculation of the perimeter of the given figure:

We know that

The circumference of a circle is 2πr,

So, the quarter circumference of a circle would be (2πr) by 4.

Now

The length of that arc should be

[tex]= (2 \times3.14 \times 8) \div 4[/tex]

= 12.56

Now the perimeter is

= 12.56 + 8 + 10 + 10 + 17 + 9

= 66.56 cm

Therefore, The perimeter of the given figure is 66.56 cm

Learn more about perimeter here: https://brainly.com/question/24422266