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A sailor pulls a boat horizontally alongside a dock for 10.0 m with a rope angled at 40.0°. He uses a force of 100.0 N. How much work did he do on the boat?

Respuesta :

First, we find the horizontal component of the force.
Fx = Fcos∅
Fx = 100 cos(40)
Fx = 76.6 Newtons

Work = Force x distance
Work = 76.6 x 10
Work = 766 Joules