xoxolilly
contestada

How many grams of magnesium metal will react completely with 4.8 liters of 5.0 M HCl? Show all of the work needed to solve this problem.

Respuesta :

Answer:

291.72 grams of magnesium metal will react completely with 4.8 liters of 5.0 M HCl.

Explanation:

Molarity of teh HCl solution = 5.0 M

Volume of HCl solution = 4.8 L

[tex]Molarity=\frac{\text{Number of moles Moles}}{\text{Volume of the solution (L)}}[/tex]

[tex]5.0 M=\frac{Moles}{4.8 L}[/tex]

Moles of HCl = 24 moles

[tex]Mg+2HCL\rightarrow MgCl_2+H_2[/tex]

According to reaction , 2 moles of HCl reacts with 1 mole magnesium.

Then 24 moles of HCl will react with:

[tex]\frac{1}{2}\times 24 mol=12 mol[/tex] of magnesium

Mass of 12 mol of magnesium =24.31 g/mol × 12 mol = 291.72 g

291.72 grams of magnesium metal will react completely with 4.8 liters of 5.0 M HCl.

sebassandin

Answer:

[tex]m_{Mg}=291.6gMg[/tex]

Explanation:

Hello,

At first the balanced chemical reaction between magnesium metal and hydrochloric acid is shown below:

[tex]Mg+2HCl-->MgCl_2+H_2[/tex]

Magnesium grams are computed via the following stoichiometric procedure considering a 1/2 by mole relationship between magnesium and hydrochloric acid in the chemical reaction:

[tex]m_{Mg}=5.0\frac{molHCl}{L}*4.8L*\frac{1molMg}{2molHCl}*\frac{24.3gMg}{1molMg}\\m_{Mg}=291.6gMg[/tex]

Best regards.

Otras preguntas