Answer:
[tex](\frac{4a+4}{2a})\times(\frac{a^2}{a+1})=2a[/tex]
Step-by-step explanation:
Given : Expression [tex](\frac{4a+4}{2a})\times(\frac{a^2}{a+1})[/tex]
To find : The given expression is equivalent to?
Solution :
Write the given expression,
[tex](\frac{4a+4}{2a})\times(\frac{a^2}{a+1})[/tex]
Taking 4 common from first bracket
[tex]=\frac{4(a+1)a^2}{2a(a+1)}[/tex]
Cancel the (a+1) from numerator and denominator,
[tex]=\frac{4a^2}{2a}[/tex]
Cancel the 2a from numerator and denominator,
[tex]=2a[/tex]
Therefore, The given expression is equivalent to
[tex](\frac{4a+4}{2a})\times(\frac{a^2}{a+1})=2a[/tex]
