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Please answer!
If the thermal energy of the system increases by 600 jewels and 1400 J of heat were added to the system how much work did the system do

600J

800J

1,400J

2,000J

Respuesta :

Answer: The work done by the system is 800 Joules.

Explanation:

Internal change in thermal energy of the system,[tex]\Delta U[/tex]= 600 Joules

Energy added to the system the system,Q = 1400 Joules

Work done by the system can be calculated by using First law of thermodynamics:'

[tex]\Delta U=Q-W[/tex] (First law of thermodynamics)

[tex]600 J=1400 J-W[/tex]

[tex]W=Q-\Delta U=1400 J-600 J=800 J[/tex]

The work done by the system is 800 Joules.

Answer:

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Explanation:

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