NH3- 17g/mol and SF6-146 g/mol
Well 1 mole of SF6 is 146.048 grams (i added hte atomic masses of each element). So then the number of moles in 0.85 grams would be 0.00582000438 moles.
= 1mole / 146.048g * 0.85g
so we would need 0.00582000438 moles of NH3 to have the same number of molecules.
One mole of NH3 is 17.030519999989988 grams (i added each atoms mass). so 0.00582000438 moles of NH3 would be:
= 17.030519999989988 g / mole * 0.00582000438moles
that equals 0.09911770099 grams.
so 0.09911770099 grams is the answer if you rounded, you get about 0.1 grams