We can answer this question using sine rule, as I'm sure you're aware of since you have drawn out the opposite angles and sides.
In case you need reminding, the sine rule is as follows:
[tex] \frac{sin(A)}{a} = \frac{sin(B)}{b} = \frac{sin(C)}{c} [/tex]
Using the information you have provided, we can set A to be x, a to be 33 (as it's the opposite), B to be 102, and b to be 73 (again, as it's the opposite).
If we plug these values in to the sine rule, we get:
[tex] \frac{sin(X)}{33}= \frac{sin(102)}{73} [/tex]
Now all we have to do is rearrange to find X.
[tex]arcsine(33(\frac{sin(102)}{73})) = 26.2 [/tex] to 1DP
