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An object which is vertically projected or falls from the sky has a velocity of 'v' and is given by: v = -32t + vo, where 'v' is the velocity in feet/sec, 't' is the time in seconds, and 'vo' is the initial velocity in feet per second. If the initial velocity is 195 feet/sec, and the velocity v is in the range of 3 < v < 99, find the time interval t.

Respuesta :

Lowest Range would be: 
3 = -32t + 195
-32t = 3 - 195
t = -192 / -32
t = 6

Greatest Range = 99 = -32t + 195
-32t = 99 - 195
t = -96 / -32
t = 3

In short, Your Time Interval would be: 3 < t < 6

Hope this helps!

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