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A submerged submarine alters its buoyancy so that it initially accelerates upward at 0.325 m/s^2. What is the submarine's average density at this time? (Hint: the density of sea water is 1.025x10^3 kg/m^3.)

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MissPhiladelphia
You are given a submerged submarine accelerating upward at 0.325 m/s² and the density of sea water is 1.025x10³ kg/m³. The submarine's average density at this time is 22 kg/m³.
onyebuchinnaji

The submarine's average density at this time is 992.1 kg/m³.

What is buoyant force?

The buoyant force of an object is the upward force of the object due to its weight displaced by a fluid.

The upward force of the submarine

[tex]F_n = m(a + g)[/tex]

where;

  • m is the mass of the submarine

The buoyant of the submarine

[tex]F_b = \rho Vg[/tex]

  • V is the volume of the submarine submerged

The upward force is equal to buoyant force

[tex]m(a + g) = \rho Vg \\\\\frac{m}{V} = \frac{\rho g}{a + g} \\\\\rho_s = \frac{\rho g}{a + g}[/tex]

where;

  • [tex]\rho _s[/tex] is the average density of the submarine

[tex]\rho _ s = \frac{\rho g}{a + g}\\\\\rho _s = \frac{1.025 \times 10^3 \times 9.8}{0.325 + 9.8} \\\\\rho_s = 992.1 \ kg/m^3[/tex]

Thus, the submarine's average density at this time is 992.1 kg/m³.

Learn more about average density here: https://brainly.com/question/11730603

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