Elsakabeche
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From a group of 6 candidates, a committee of 2 people is selected. In how many different ways can the committee be selected? I know the answer is 15 ways , but how do you do it ? 30 points

Respuesta :

Kerbal27
This is a combination problem. 

6 nCr 2

[tex] \frac{6!}{2! * (6-2)!} = \frac{720}{48}=15 [/tex]

Answer:

15

Step-by-step explanation:

Here we have to use the combination formula.

nCr = n! / r! (n - r)!

Given: n = 6 and r = 2

Plugging in the given values, we get

6C2 = 6! / 2!(6 - 2)!

= 6! / 2! 4!

6! = 1*2*3*4*5*6 = 720

4! = 1*2*3*4 = 24

2! = 1*2 = 2

6C2 =  720 / 2*24

= 720/48

= 15

We can select in 15 different ways.

Hope this will helpful.

Thank you.

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