notice the picture below, see the length "l"?
well [tex]\bf Area=l\times w\qquad
\begin{cases}
l=\frac{11}{4}w\\
Area=180
\end{cases}\\\\
-----------------------------\\\\
thus
\\\\
180=\cfrac{11}{4}w\times w[/tex]
solve for "w", to find the width,
what's the length? well, l = 11/4 w
