Respuesta :
The heat required to completely boil away 0.200 kg of water is 4.52 × 102 kJ.
We will use the formula:
Q = ml
where Q is the heat, m is the mass of substance, and l is the latent heat of vaporization of the substance.
Q = 0.2 x 2.26 x 10³
Q = 452 kJ
Q = ml
where Q is the heat, m is the mass of substance, and l is the latent heat of vaporization of the substance.
Q = 0.2 x 2.26 x 10³
Q = 452 kJ