Answer:
16.8
Step-by-step explanation:
To find how many times larger (1.008 × 10¹) is than (6 × 10⁻¹), divide the first expression by the second expression:
[tex]\implies \dfrac{1.008 \times 10^1}{6 \times 10^{-1}}[/tex]
[tex]\textsf{Apply the fraction rule} \quad \dfrac{ab}{cd}=\dfrac{a}{c} \times \dfrac{b}{d}:[/tex]
[tex]\implies \dfrac{1.008}{6} \times \dfrac{10^1}{10^{-1}}[/tex]
Divide the numbers 1.008 and 6:
[tex]\implies 0.168 \times \dfrac{10^1}{10^{-1}}[/tex]
[tex]\textsf{Apply the exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:[/tex]
[tex]\implies 0.168 \times 10^{(1-(-1)}[/tex]
Simplify:
[tex]\implies 0.168 \times 10^{2}[/tex]
[tex]\implies 0.168 \times 10 \times 10[/tex]
[tex]\implies 1.68 \times 10[/tex]
[tex]\implies 16.8[/tex]
