The value of van't Hoff factor for the electrolyte is i = 0.28
Molarity of solution = 5.61 m
The temperature which depresses the freezing point of water = 2.93 °C
The freezing point depression constant, kfp, for water = 1.86 °C kg[tex]mol^{-1}[/tex]
To find the van't Hoff factor, let's use the following formula.
ΔTf = kf × molality × i
Here ΔTf = depression fo freezing point
kf = freezing point depression constant
i = Van't Hoff's factor
Now substitute the values in the above formula.
2.93 = 1.86 x 5.61 x i
i = 2.93 / 1.86 x 5.61
i = 2.93 / 1.043 = 0.28
Hence, the value of van't Hoff factor is 0.28
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The complete question is:
A 05.61 m solution of unknown electrolyte depresses the freezing point of water by 2.93 °C. What is van't Hoff factor for this electrolyte? The freezing point depression constant (Kf) for water is 1.86 °C kg[tex]mol^{-1}[/tex].
