Answer:
[tex]x=0, \quad x=3[/tex]
Step-by-step explanation:
Given equation:
[tex]9x^2-27x=0[/tex]
Factor out the common term 9x:
[tex]\implies 9x(x-3)=0[/tex]
Zero Product Property: If a⋅b = 0 then either a = 0 or b = 0 (or both).
Using the Zero Product Property, set each factor equal to zero and solve for x:
[tex]\begin{aligned}\underline{\sf Case\; 1} & & \underline{\sf Case \;2}\\9x&=0 & x-3&=0\\\dfrac{9x}{9} & =\dfrac{0}{9} & \quad \quad x-3+3 & =0+3\\x&=0 & x&=3\end{aligned}[/tex]
Therefore, the solutions to the given equation are:
[tex]x=0, \quad x=3[/tex]
