95% confidence interval for the true population mean watermelon weight. is (69.94, 72.06)
Confidence Interval formula = Mean ± z × Standard deviation/√n
Mean = 71 ounces
Standard deviation = 2.8 ounces
z score = 95% confidence interval = 1.96
Confidence Interval = 71 ± 1.96 × 2.8/√27
= 71 ± 1.96 × 0.5388602512
= 71 ± 1.0561660924
71 - 1.0561660924
= 69.943833908 ounces
Approximately = 69.94 ounces
71 + 1.0561660924
= 72.0561660924 ounces
Approximately = 72.06 ounces
95% Confidence Interval = (69.94, 72.06).
the complete question is
You measure 27 watermelons' weights, and find they have a mean weight of 71 ounces. Assume the population standard deviation is 2.8 ounces. Based on this, construct a 95% confidence interval for the true population mean watermelon weight.
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