The no. of moles of [tex]CH_4[/tex] remaining after the reaction is found to be 11.5 moles.
The no. of moles of a material equals the ratio of its given mass to the mass of one mole of that molecule in a chemical reaction.
The coefficients reflect the number of moles, not simply molecules, that react.
Stoichiometric coefficients are the numbers that come before the chemical formula of a molecule participating in a reaction. They assist us in determining the relative amounts or no. of moles of each reactant consumed and product created during a reaction.
[tex]CH_4 (g) + 2O_2 (g) \rightarrow CO_2 (g) + 2H_2O (g)[/tex]
No. of moles of [tex]CH_4[/tex] = 13.0 mol
No. of moles of [tex]O_2[/tex] = 3.0 mol
Here [tex]O_2[/tex] is limiting reagent because moles of [tex]O_2[/tex] is less.
Thus, [tex]CH_4[/tex] is in excess
1 mol [tex]CH_4[/tex] = 2 mol [tex]O_2[/tex]
x mol [tex]CH_4[/tex] = 3 mol [tex]O_2[/tex]
Moles of [tex]CH_4[/tex] used = 3 x 1 / 2 = 1.5 mol
Here we have 13 moles of [tex]CH_4[/tex],
Therefore,
No. of moles of [tex]CH_4[/tex] left = 13 - 1.5 = 11.5
Result:
11.5 moles of [tex]CH_4[/tex] will remain after the reaction.
Learn more about No. of moles used in a reaction here:
https://brainly.com/question/15364329
#SPJ4