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acceptance sampling is a statistical method used to monitor the quality of purchased parts and components. to ensure the quality of incoming parts, a purchaser or manufacturer normally samples 20 parts and allows one defect.

Respuesta :

Let X represent the number of defects.

When n=20 and p = 0.01,

Likelihood = P(Acceptance) = P(X=0) + P(X=1)

= 20C0 * (0.01)^0 * (1-0.01)^(20) + 20C1 * (0.01)^1 * (1-0.01)^(20-1) = 0.9831

When n=20 and p = 0.02,

Likelihood = P(Acceptance) = P(X=0) + P(X=1)

= 20C0 * (0.02)^0 * (1-0.02)^(20) + 20C1 * (0.02)^1 * (1-0.02)^(20-1) = 0.9401

When n=20 and p = 0.05,

Likelihood = P(Acceptance) = P(X=0) + P(X=1)

= 20C0 * (0.05)^0 * (1-0.05)^(20) + 20C1 * (0.05)^1 * (1-0.05)^(20-1) = 0.7358

Learn more about combination here:

brainly.com/question/12725706

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